2023 Kiskút Open

This was the first edition of the tournament.^[1]

Bogdan Bobrov and Sergey Fomin won the title after defeating Sarp Ağabigün and Ergi Kırkın 6–2, 5–7, [11–9] in the final.

Seeds

First round					Quarterfinals					Semifinals					Final

					1	A-u-H Qureshi R Ramanathan	6⁴	3
	S Ağabigün E Kırkın	6	6			S Ağabigün E Kırkın	7⁷	6
	K Coppejans N Sánchez Izquierdo	2	2								S Ağabigün E Kırkın	6	2	[10]
4	F Bergevi P Tsitsipas	4	6	[10]							M Guinard N Serdarušić	1	6	[4]
WC	Matyas Füle G Madarász	6	3	[8]	4	F Bergevi P Tsitsipas	5	6¹
	S Diez M Vrbenský	3	4			M Guinard N Serdarušić	7	7⁷
	M Guinard N Serdarušić	6	6													S Ağabigün E Kırkın	2	7	[9]
WC	Attila Boros Botond Kisantal	3	6	[8]												B Bobrov S Fomin	6	5	[11]
Alt	Rimpei Kawakami A Šetkić	6	3	[10]	Alt	R Kawakami A Šetkić	6	3	[8]
					3	P Raja D Sharan	3	6	[10]
										3	P Raja D Sharan	6³	3
	S Fayziev I Gakhov	3	6⁵								B Bobrov S Fomin	7⁷	6
	B Bobrov S Fomin	6	7⁷			B Bobrov S Fomin	6	6
					2	V Manafov O Prihodko	4	4

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