| Chorula | |
|---|---|
| Village | |
|  Church | |
|   Chorula | |
| Coordinates: 50°32′N 17°58′E / 50.533°N 17.967°E | |
| Country |  Poland | 
| Voivodeship | Opole | 
| County | Krapkowice | 
| Gmina | Gogolin | 
| Population | 640 | 
| Website | http://www.chorula.pl/ | 
Chorula [xɔˈrula] is a village in the administrative district of Gmina Gogolin, within Krapkowice County, Opole Voivodeship, in south-western Poland.[1] It lies approximately 7 kilometres (4 mi) north-west of Gogolin, 8 km (5 mi) north of Krapkowice, and 15 km (9 mi) south of the regional capital Opole.
References
    This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.
