1895 Iowa gubernatorial election
November 5, 1895
 
Nominee Francis M. Drake Washington I. Babb Sylvester B. Crane
Party Republican Democratic Populist
Popular vote 208,708 149,428 32,189
Percentage 52.00% 37.23% 8.02%
Results by county
Drake:      40–50%      50–60%      60–70%      70–80%
Babb:      40–50%      50–60%      60–70%
Crane:      40–50%
Governor before election

Frank D. Jackson
Republican

 Elected Governor

Francis M. Drake
Republican

The 1895 Iowa gubernatorial election was held on November 5, 1895. Republican nominee Francis M. Drake defeated Democratic nominee Washington I. Babb with 52.00% of the vote.

General election

Candidates

Major party candidates

  • Francis M. Drake, Republican
  • Washington I. Babb, Democratic

Other candidates

  • Sylvester B. Crane, People's
  • Francis Bacon, Prohibition

Results

1895 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Francis M. Drake 208,708 52.00%
Democratic Washington I. Babb 149,428 37.23%
Populist Sylvester B. Crane 32,189 8.02%
Prohibition Francis Bacon 11,014 2.74%
Majority 59,280
Turnout
Republican hold Swing +2.26%

References

  1. ↑ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 8, 2020.
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