1916 Iowa gubernatorial election
November 7, 1916
 
Nominee William L. Harding Edwin T. Meredith
Party Republican Democratic
Popular vote 313,586 186,832
Percentage 61.03% 36.36%
Governor before election

George W. Clarke
Republican

 Elected Governor

William L. Harding
Republican

The 1916 Iowa gubernatorial election was held on November 7, 1916. Republican nominee William L. Harding defeated Democratic nominee Edwin T. Meredith with 61.03% of the vote.

General election

Candidates

Major party candidates

  • William L. Harding, Republican
  • Edwin T. Meredith, Democratic

Other candidates

  • John W. Bennett, Socialist
  • Oren D. Ellett, Prohibition
  • Stephen H. Bashor, Progressive
  • Arthur S. Dowler, Socialist Labor

Results

1916 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William L. Harding 313,586 61.03%
Democratic Edwin T. Meredith 186,832 36.36%
Socialist John W. Bennett 8,200 1.60%
Prohibition Oren D. Ellett 2,880 0.56%
Progressive Stephen H. Bashor 2,035 0.40%
Socialist Labor Arthur S. Dowler 315 0.06%
Majority 126,754
Turnout
Republican hold Swing

References

  1. ↑ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 2, 2020.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.